Thursday, December 29, 2016
Monday, December 19, 2016
Friday, November 4, 2016
Answers to select problems from yesterdays Homework
37) 4pi/5
41) It is not defined by the range so we cannot use the formula directly as in problem 37. However, we can find a reference angle in the interval (-pi/2, pi/2). The angle of sin(9pi/8) is in quadrant III so it is negative. The reference angle of 9pi/8 is pi/8. Since pi/8 is in the interval of -pi/2 to pi/2. We can apply the equation to get the answer. Remember that sin is negative. So the answer is -pi/8.
37) 4pi/5
41) It is not defined by the range so we cannot use the formula directly as in problem 37. However, we can find a reference angle in the interval (-pi/2, pi/2). The angle of sin(9pi/8) is in quadrant III so it is negative. The reference angle of 9pi/8 is pi/8. Since pi/8 is in the interval of -pi/2 to pi/2. We can apply the equation to get the answer. Remember that sin is negative. So the answer is -pi/8.
Monday, October 31, 2016
Tuesday, October 18, 2016
Homework due Thursday 10/20/2016
Homework book pg. 28 # 118, 119, 132-136
Study for Quiz on Thursday on unit 5.3
Study for Quiz on Thursday on unit 5.3
Monday, October 17, 2016
Homework due Tuesday 10/18/2016
pg. 24 # 45, 53 , 55
pg. 26 # 59-65 odd, 77-81 odd, 89, 91, 95-102, 109
pg. 26 # 59-65 odd, 77-81 odd, 89, 91, 95-102, 109
Friday, October 14, 2016
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